The specific resistance ρ of a circular wire of radius r. Resistance R and and length l is given by $\rho = \frac{{{\rm{\pi }}{r^2}R}}{l}.$ Given, $r = 0:\left( {24 \pm 0.02} \right)cm,\,R = \left( {30 \pm 1} \right){\rm{\Omega }}$ and $l = \left( {4.80 \pm 0.01} \right)cm.$ The percentage error in ρ is nearly

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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The specific resistance ρ of a circular wire of radius r. Resistance R and and length l is given by

\rho = \frac{{\mathrm{\pi }{r^2}R}}{l}.

Given,

r = 0:\left( {24 \pm 0.02} \right)cm,\,R = \left( {30 \pm 1} \right)\mathrm{\Omega }

and

l = \left( {4.80 \pm 0.01} \right)cm.

The percentage error in ρ is nearly

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Correct option: D

0.202

Option D (0.202) is correct because it involves calculating the percentage error in specific resistance using the given formula and error values for r, R, and l.

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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