JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

The area enclosed between the parabolas

y^2=4 x

and

x^2=4 y

View answer and explanation

Correct option: D

\frac{16}{3}

sq. unit

Option D (

\frac{16}{3}

sq. unit) is correct because the area enclosed between the parabolas

y^2=4x

and

x^2=4y

is found by integrating the difference of the functions from 0 to 4, which results in

\frac{16}{3}

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