Oxidation number of carbon in carbon sub oxide $\left( {{{\bf{C}}_{\bf{3}}}{{\bf{O}}_{\bf{2}}}} \right)$

JEE CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1

Oxidation number of carbon in carbon sub oxide

\left( {{\mathbf{C}_\mathbf{3}}{\mathbf{O}_\mathbf{2}}} \right)

View answer and explanation

Correct option: B

+ \frac{4}{3}

Option B (

+ \frac{4}{3}

) is correct because the average oxidation number of carbon in carbon suboxide is calculated to be +4/3.

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.