$\mathop {\lim }\limits_{x \to 1} \frac{{\tan \left( {{x^2} - 1} \right)}}{{x - 1}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

\lim\limits_{x \to 1} \frac{{\tan \left( {{x^2} - 1} \right)}}{{x - 1}}

is equal to

View answer and explanation

Correct option: A

Option A (2) is correct because by applying L'Hopital's rule, the limit can be evaluated to 2.

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