JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

D=\left|\begin{array}{ccc}1 & \cos \theta & 1 \\ -\sin \theta & 1 & -\cos \theta \\ -1 & \sin \theta & 1\end{array}\right|

f(x)

5^2 \theta

then

D

lies in the interval

View answer and explanation

Correct option: C

[2-\sqrt{2}, 2+\sqrt{2}]

Option C (

[2-\sqrt{2}, 2+\sqrt{2}]

) is correct because by expanding the determinant and simplifying the expression, we can find the range of values for D.

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