JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Medium

1 of 1

Analyzing +4 | -1

2\,\,\sin \,\,\frac{A}{2} = \sqrt {1 + \sin \,\,A} + \sqrt {1 - \sin \,\,A}

, then

\frac{A}{2}

lies between

View answer and explanation

Correct option: A

2n\;\pi + \frac{\pi }{4}

and

2n\;\pi + \frac{{3\,\pi }}{4},\;\,n \in Z

Option A (

2n\\;\pi + \frac{\pi }{4}

and

2n\\;\pi + \frac{{3\\,\pi }}{4},\;\,n \in Z

) is correct because it defines the interval where

\frac{A}{2}

lies, based on the given equation and trigonometric properties.

More Questions from TRIGONOMETRIC EQUATIONS

Practice All Chapter MCQs →

\sin \,\,x\,\,\;cos\,\,3x = \sin \,\,3x\,\,\cos \,\,5x

\left[ {0,\;\,\frac{\pi }{2}} \right]

\left( {x,\,y} \right)

x,\,\,y \in \left[ {0,10} \right]

\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1

\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

\sin x+\cos x=\frac{\sqrt{7}}{2}

x \in\left[0, \frac{\pi}{4}\right]

\tan \frac{x}{2}

\tan \frac{\pi}{5}+2 \tan \frac{2 \pi}{5}+4 \cot \frac{4 \pi}{5}

0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x