The value of $\mathop {\lim }\limits_{x \to 0} \frac{{\left( {1 - \cos 2x} \right)}}{{{x^2}}}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

The value of

\lim\limits_{x \to 0} \frac{{\left( {1 - \cos 2x} \right)}}{{{x^2}}}

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Correct option: D

Option D (2) is correct because applying the trigonometric identity and the standard limit yields a value of 2.

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