JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The radiation is emitted when a hydrogen atom goes from a higher energy state to a lower energy state. The wavelength of one line in visible region of atomic spectrum of hydrogen is

6.63 \times 10^{-7} \mathrm{~m}

. Energy difference between the two states is

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Correct option: A

3.0 \times 10^{-19} \mathrm{~J}

Option A (3.0 x 10⁻¹⁹ J) is correct because the energy difference between the two states is calculated using the formula E = hc/λ.

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