If $\overrightarrow A = 2\hat i + 3\hat j + 4\hat k\,\,and\,\,{\rm{\vec B}} = 4\hat i + 3\hat j + 2\hat k$, then angle between $\overrightarrow A $ and ${\rm{\vec B}}$ is

${\sin ^{ - 1}}\left( {25/29} \right)$

${\sin ^{ - 1}}\left( {29/25} \right)$

${\cos ^{ - 1}}\left( {29/25} \right)$

NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

\overrightarrow A = 2\hat i + 3\hat j + 4\hat k\,\,and\,\,\mathrm{\vec B} = 4\hat i + 3\hat j + 2\hat k

, then angle between

\overrightarrow A

and

\mathrm{\vec B}

View answer and explanation

Correct option: C

{\cos ^{ - 1}}\left( {25/29} \right)

Option C (

{\cos ^{ - 1}}\left( {25/29} \right)

) is correct because it is the angle between the two vectors calculated using the dot product formula.

Practice All Chapter MCQs →

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)