JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1

A very small circular loop of radius

a

is initially (at

t=0

) co-planar and concentric with a much larger fixed circular loop of radius

b

. A constant current

I

flows in the larger loop. The smaller loop is rotated with a constant angular speed

\omega

about the common diameter. The emf induced in the smaller loop as a function of time

t

View answer and explanation

Correct option: C

\frac{\pi a^2 \mu_0 I}{2 b} \omega \sin \omega t

Option C (

\frac{\pi a^2 \mu_0 I}{2 b} \omega \sin \omega t

) is correct because it is the induced emf calculated using the formula

e=N B A \omega \sin \omega t

with appropriate substitutions.

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R

n

i=i_0 \sin \omega t

N

4 \mathrm{sec}

0.1\,\,{m^2}

\mathrm{60}

\mathrm{0}\mathrm{.4}\,\,\mathrm{T}

\mathrm{100}

\mathrm{50}\,\,\mathrm{mH}

\mathrm{2 A}