$P$ is a point on the axis of a convex mirror. The image of $P$ formed by the mirror, coincides with $P$. A rectangular glass slab of thickness $t$ and refractive index ${\rm{\mu }}$ is now introduced between $P$ and the mirror. For the image of P to coincide with $P$ again, the mirror must be moves

Towards $P$ by $t\,\,\left( {1 - \,\,\frac{1}{{\rm{\mu }}}} \right)$

Towards $P$ by $\left( {{\rm{\mu }} - 1} \right)\,\,t$

Away from $P$ by $\left( {{\rm{\mu }} - 1} \right)\,\,t$

Away from $P$ by $t\,\,\left( {1 - \,\,\frac{1}{{\rm{\mu }}}} \right)$

JEE PHYSICS MCQ: RAY OPTICS

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Application +4 | -1

P

is a point on the axis of a convex mirror. The image of

P

formed by the mirror, coincides with

P

. A rectangular glass slab of thickness

t

and refractive index

\mathrm{\mu }

is now introduced between

P

and the mirror. For the image of P to coincide with

P

again, the mirror must be moves

View answer and explanation

Correct option: C

Towards

P

t\,\,\left( {1 - \,\,\frac{1}{\mathrm{\mu }}} \right)

The correct answer is C (Towards

P

t\,\left( {1 - \,\frac{1}{\mathrm{\mu }}} \right)

) because the mirror needs to compensate for the apparent shift in position due to the glass slab.