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JEE MATHEMATICS MCQ: INCREASING & DECREASING

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Let f(x)=cot⁡−1{g(x)},f\left( x \right) = {\cot ^{ - 1}}\left\{ {g\left( x \right)} \right\}, where g(x)g\left( x \right) is an increasing function on the interval (0,π).\left( {0,\pi } \right). Then, f(x)f\left( x \right) is
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Correct option: B
Decreasing on (0,π)\left( {0,\pi } \right)
Option B (Decreasing on (0,π\pi)) is correct because the derivative of f(x) is negative on the interval (0,π\pi), indicating that the function is decreasing.

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