In an experiment 50 mL of 0.1 $M$ solution of a salt reacted with 25 mL of 0.1 $M$ solution of sodium sulphite. The half equation for the oxidation of ${\rm{SO}}_3^{2 - }\left( {aq} \right) + {{\rm{H}}_2}{\rm{O}}\left( l \right) \to {\rm{SO}}_4^{2 - }\left( {aq} \right) + 2{{\rm{H}}^ + }\left( {aq} \right) + 2{e^ - }$ If the oxidation number of metal in the salt was 3, what would be the new oxidation number of metal?

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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In an experiment 50 mL of 0.1

M

solution of a salt reacted with 25 mL of 0.1

M

solution of sodium sulphite. The half equation for the oxidation of

\mathrm{SO}_3^{2 - }\left( {aq} \right) + {\mathrm{H}_2}\mathrm{O}\left( l \right) \to \mathrm{SO}_4^{2 - }\left( {aq} \right) + 2{\mathrm{H}^ + }\left( {aq} \right) + 2{e^ - }

If the oxidation number of metal in the salt was 3, what would be the new oxidation number of metal?

View answer and explanation

Correct option: C

Option C (2) is correct because the change in oxidation number of the metal is 1, resulting in a new oxidation number of 2.