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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
123. If ∑n=151n(n+1)(n+2)(n+3)=k3\sum_{n=1}^{5} \frac{1}{n(n+1)(n+2)(n+3)}=\frac{k}{3}, then k\mathrm{k} is equal to
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Correct option: C
55336\frac{55}{336}
Option C (55336\frac{55}{336}) is correct because it results from correctly applying partial fraction decomposition and telescoping the series.

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