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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Let ff be a continuous function satisfying ∫−πt2(f(x)+x2)dx=π+43t3\int\limits_{{-\pi}}^{t^2}\left(f(x)+x^2\right) \mathrm{d} x=\pi+\frac{4}{3} t^3 for all tt, then f(π2/4)f\left(\pi^2 / 4\right) is equal to
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Correct option: D
π−π416\pi-\frac{\pi^4}{16}
Option D (π−π416\pi-\frac{\pi^4}{16}) is correct because differentiating the given equation and substituting t=π2t = \frac{\pi}{2} yields the value of f(π24)f(\frac{\pi^2}{4}).

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