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JEE MATHEMATICS MCQ: RATE MEASURE

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The distance ss meters covered by a body in t seconds,is given by s=3t2−8t+5.s = 3{t^2} - 8t + 5. The body will stop after
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Correct option: C
43s\frac{4}{3}s
Option C (43s\frac{4}{3}s) is correct because it represents the time at which the velocity of the body becomes zero, indicating that the body has stopped.

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