When one mole of ${\rm{KMn}}{{\rm{O}}_4}$ reacts with $HCl$, the volume of chlorine liberated at $NTP$ will be:

NEET UG CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Hard

1 of 1

Application +4 | -1

When one mole of

\mathrm{KMn}{\mathrm{O}_4}

reacts with

HCl

, the volume of chlorine liberated at

NTP

will be:

View answer and explanation

Correct option: D

56.0 litre

Option D (56.0 litre) is correct because the reaction of 2 moles of

KMnO_4

with HCl liberates 5 moles of

Cl_2

, which corresponds to 56.0 L at NTP for 1 mole of

KMnO_4