JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

a = \lim\limits_{n \to \infty } \sum\limits_{k = 1}^n {\frac{{2n}}{{{n^2} + {k^2}}}}

and

f(x)=\sqrt{\frac{1-\cos x}{1+\cos x}}, x \in(0,1)

, then

View answer and explanation

Correct option: C

\sqrt{2} f\left(\frac{a}{2}\right)=f^{\prime}\left(\frac{a}{2}\right)

Option C (

\sqrt{2} f(\frac{a}{2})=f^{\prime}(\frac{a}{2})

) is correct because after calculating

a

and simplifying

f(x)

, we find that the given relation holds true.

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