JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim\limits_{x \to \infty } \left[ {\frac{{{x^3} + 1}}{{{x^2} + 1}} - \left( {ax + b} \right)} \right] = 2

, then

View answer and explanation

Correct option: C

a = 1

and

b = - 2

Option C (

a = 1

and

b = - 2

) is correct because these values ensure that the limit exists and equals 2 when x approaches infinity.

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