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JEE PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1
The function sin⁡2(ωt)\sin ^2(\omega t) represents:
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Correct option: B
A periodic, but not simple harmonic motion with a period π/ω\pi / \omega
Option B is correct because sin⁡2(ωt)\sin^2(\omega t) is a periodic function but not a simple harmonic motion, and its period is π/ω\pi/\omega.

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