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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A body projected vertically upwards with a certain speed from top of a tower, reaches the ground in time t1.t_1. If it is projected vertically downwards with same speed from same point, it reach the ground in the time t2.t_2. Time required for it to reach the ground if it dropped from the same point and projected horizontally with same speed, respectively are
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Correct option: D
t1t2,t1t2\sqrt{t_1 t_2}, \sqrt{t_1 t_2}
The correct answer is D (t1t2,t1t2\sqrt{t_1 t_2}, \sqrt{t_1 t_2}) because the time to fall when dropped is the geometric mean of the times when projected upwards and downwards, and the time for horizontal projection is the same as dropping.

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