JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

Equation of the ellipse whose foci are (2,2) and (4,2) and the major axis is of length 10 is

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Correct option: D

\frac{{{{\left( {x - 3} \right)}^2}}}{{25}} + \frac{{{{\left( {y - 2} \right)}^2}}}{{24}} = 1

Option D (

\frac{{{{\left( {x - 3} \right)}^2}}}{{25}} + \frac{{{{\left( {y - 2} \right)}^2}}}{{24}} = 1

) is correct because it satisfies the given foci and major axis length for an ellipse centered at (3, 2).

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

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9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O