JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

Given that

\alpha, \gamma

are roots of the equation

A x^2-4 x+1=0

and

\beta, \delta

are the roots of the equation

B x^2-6 x+1=0

, then values of

A

and

B

such that

\alpha, \beta, \gamma

and

\delta

are in HP, are

View answer and explanation

Correct option: A

A=3, B=8

Option A (A=3, B=8) is correct because by using the properties of HP and AP, we can find the values of A and B.

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

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A-(B \cap C)

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a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}