Question

Applying the principle of homogeneity of dimensions, determine which one is correct. where $\mathrm{T}$ is time period, $\mathrm{G}$ is gravitational constant, $\mathrm{M}$ is mass, $\mathrm{r}$ is radius of orbit.

Accepted Answer

$\mathrm{T}^2=\frac{4 \pi^2 \mathrm{r}^3}{\mathrm{GM}}$

Answer

$\mathrm{T}^2=\frac{4 \pi^2 \mathrm{r}}{\mathrm{GM}^2}$

Answer

$\mathrm{T}^2=4 \pi^2 \mathrm{r}^3$

Answer

$\mathrm{T}^2=\frac{4 \pi^2 \mathrm{r}^2}{\mathrm{GM}}$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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