NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

The retardation experienced by a moving motor boat, after its engine is cut off, is given by

\frac{{du}}{{dt}} = - k{v^3},

, where k is a constant. If

{v_0}

is the magnitude of the velocity at cut-off, the magnitude of the velocity at time t after the cut-off is

View answer and explanation

Correct option: D

\frac{{{v_0}}}{{\sqrt {2v_0^2kt + 1} }}

Option D is correct because it's derived by integrating the given retardation equation and applying the initial condition.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)