JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

1 of 1

Application +4 | -1

The equation of an ellipse whose eccentricity is

\frac{1}{2}

and the vertices are,

\left( {4,0} \right)

and

\left( {10,0} \right)

View answer and explanation

Correct option: A

3{x^2} + 4{y^2} - 42x + 120 = 0

Option A (

3{x^2} + 4{y^2} - 42x + 120 = 0

) is correct because it represents the equation of an ellipse with the given eccentricity and vertices.

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

P

9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O