JEE MATHEMATICS MCQ: COMPOUND ANGLES

1 Easy

1 of 1

Application +4 | -1

A + B = 45^\circ

, then

\left( {\cot A - 1} \right)\left( {\cot B - 1} \right)

is equal to

View answer and explanation

Correct option: D

Option A (2) is correct because substituting A + B = 45° into the cotangent addition formula and simplifying leads to the result (cot A - 1)(cot B - 1) = 2.

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\tan \left( {A + B} \right) = p

and

\tan \left( {A - B} \right) = q

, then the value of

\tan \,\,2A

is The value of

\cos \,\,x\,\,\cos \,\,y\,\,\sin \,\,\left( {x - y} \right) + \cos \,\,y\,\,\cos \,\,z\,\,\sin \,\,\left( {y - z} \right)

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\sin \alpha, \cos \alpha

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\sqrt{1+\sin \alpha \cos \alpha}

for some

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. Then, the greatest angle of the triangle is If

\tan \,\,A = 2\,\,\tan \,\,B + \cot \,\,B,\;\;\mathrm{then}\;\,2\,\,\tan \left( {A - B} \right)\mathrm{\;}

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If

A,B,C

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