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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Analyzing +4 | -1
The number of real solutions of the equation tan⁡−1x2−3x+2+cos⁡−14x−x2−3=π\tan ^{-1} \sqrt{x^2-3 x+2}+\cos ^{-1} \sqrt{4 x-x^2-3}=\pi is
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Correct option: C
Zero
Option C (Zero) is correct because the given equation has no real solutions as the range of the left-hand side is strictly less than π\pi.

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