JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

The value of

\lim\limits_{x \to 2} \left\{ {{{\left[ {\frac{{{x^3} - 4x}}{{{x^3} - 8}}} \right)}^{ - 1}} - {{\left( {\frac{{x + \sqrt {2x} }}{{x - 2}} - \frac{{\sqrt 2 }}{{\sqrt x - \sqrt 2 }}} \right)}^{ - 1}}} \right\}

View answer and explanation

Correct option: A

\frac{1}{2}

Option A (

\frac{1}{2}

) is correct because after simplification and applying the limit, the expression evaluates to

\frac{1}{2}

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