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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
If ∫0π/2dxa2cos⁡2x+b2sin⁡2x=π16\int\limits_{0}^{\pi / 2} \frac{d x}{a^2 \cos ^2 x+{b}^2 \sin ^2 x}=\frac{\pi}{16}. Then minimum value of acos⁡x+bsin⁡xa \cos x+b \sin x is
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Correct option: A
−4-4
Option A (-4) is correct because the minimum value of the expression is found by relating the integral to ab and minimizing acos⁡x+bsin⁡xa \cos x + b \sin x using a=ba=b.

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