JEE MATHEMATICS MCQ: PERMUTATIONS

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Ten persons are arranged in a row. The number of ways of selecting four persons so that no two persons sitting next to each other are selected is

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Correct option: C

Option C (35) is correct because the number of ways to select four non-adjacent persons from ten is equivalent to arranging 4 ones and 6 zeros with no two ones adjacent, which can be done in

{ }^7 C_4 = 35

ways.

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