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JEE CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

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Analyzing +4 | -1
The major product of the following reaction is:
CH3−CHCl∣−CH3→(ii) HBr, peroxide(iii)aq.KOH (i) Alc. KOHC{H_3} - \mathop {CH}\limits^{\begin{array}{cccccccccccccccccccc} {Cl} \\ | \end{array}} - C{H_3}\xrightarrow[{\begin{array}{cccccccccccccccccccc} {(ii){\text{ }}HBr,{\text{ peroxide}}} \\ {\left( {iii} \right){\kern 1pt} {\kern 1pt} {\text{aq}}.{\kern 1pt} {\kern 1pt} KOH} \end{array}}]{{{\text{ }}(i){\text{ Alc}}.{\text{ }}KOH}}
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Correct option: B
CH3−CH2−CH2−OHC{H_3} - C{H_2} - C{H_2} - OH
The correct answer is B (CH3−CH2−CH2−OHC{H_3} - C{H_2} - C{H_2} - OH) because the reaction sequence involves anti-Markovnikov addition of HBr followed by substitution with KOH.

More Questions from HALOALKANES AND HALO ARENES

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An alkyl halide reacts with metallic sodium in dry ether. The reaction is known as : In electrophilic substitution reaction of chlorobenzene, the chloro group: Which of the followings statements is/are incorrect? Polymerization of alkenes takes place through Assertion (A): The boiling points of alkyl halides decrease in the order:
RI>RBr>RCI>RFRI > {R B r} > {R C I} > {R F}.

Reason (R): The boiling points of alkyl chlorides, bromides and iodides are considerably higher than that of the hydrocarbon of comparable molecular mass. Friedel-Craft’s reaction of bromobenzene with methyl iodide gives:
Type at least 2 characters or jump directly:
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