NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1

A chain of length

\text{L}

and mass

\text{M}

is held on a frictionless table with

\text{1/nth}

of its length hanging over the edge. When the chain is released find the speed of chain while leaving the table is:

View answer and explanation

Correct option: A

\mathrm{v}=\sqrt{\mathrm{gL}\left(1-\frac{1}{\mathrm{n}^2}\right)}

Option A (

\mathrm{v}=\sqrt{\mathrm{gL}\left(1-\frac{1}{\mathrm{n}^2}\right)}

) is correct because the potential energy lost as the chain slides off the table is converted into kinetic energy. By equating the potential energy lost to the kinetic energy gained, we can solve for the speed of the chain.

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