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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
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Application +4 | -1
Let f:R∈Rf: R \in R be a continuous function given by f(x+y)=f(x)+f(y)f(x+y)=f(x)+f(y) for all x,y∈Rx, y \in R.
If ∫02f(x)dx=α\int_0^2 f(x) d x=\alpha, then ∫−22f(x)dx\int_{-2}^2 f(x) d x is equal to
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Correct option: C
0
The correct answer is C (0) because the given functional equation implies that f(x) is of the form λx\lambda x, making it an odd function, and the integral of an odd function over a symmetric interval is zero.

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