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JEE MATHEMATICS MCQ: COMPOUND ANGLES

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An angle α\alpha is divided into two parts so that the ratio of the tangents of these parts is λ\lambda. If the difference between these parts is xx then sin⁡x/sin⁡α\sin x / \sin \alpha is equal to
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Correct option: C
λ−1λ+1\frac{\lambda-1}{\lambda+1}
Option C, λ−1λ+1\frac{\lambda-1}{\lambda+1}, is correct because it directly follows from applying the tangent subtraction and addition formulas and then using the sine subtraction and addition formulas.

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If tan⁡(A+B)=p\tan \left( {A + B} \right) = p and tan⁡(A−B)=q\tan \left( {A - B} \right) = q, then the value of tan⁡  2A\tan \,\,2A is The value of cos⁡  x  cos⁡  y  sin⁡  (x−y)+cos⁡  y  cos⁡  z  sin⁡  (y−z)\cos \,\,x\,\,\cos \,\,y\,\,\sin \,\,\left( {x - y} \right) + \cos \,\,y\,\,\cos \,\,z\,\,\sin \,\,\left( {y - z} \right)

+cos⁡  z  cos⁡  x  sin⁡  (z−x)+sin⁡  (x−y)sin⁡  (y−z)  sin⁡  (z−x)+ \cos \,\,z\,\,\cos \,\,x\,\,\sin \,\,\left( {z - x} \right) + \sin \,\,\left( {x - y} \right)\sin \,\,\left( {y - z} \right)\,\,\sin \,\,\left( {z - x} \right), is
The sides of a triangle are sin⁡α,cos⁡α\sin \alpha, \cos \alpha and 1+sin⁡αcos⁡α\sqrt{1+\sin \alpha \cos \alpha} for some 0<α<π20<\alpha<\frac{\pi}{2}. Then, the greatest angle of the triangle is If tan⁡  A=2  tan⁡  B+cot⁡  B,    then   2  tan⁡(A−B)  \tan \,\,A = 2\,\,\tan \,\,B + \cot \,\,B,\;\;\mathrm{then}\;\,2\,\,\tan \left( {A - B} \right)\mathrm{\;} is equal to

If A,B,CA,B,C are angles of a triangle, then the minimum value of tan⁡2  A2+tan⁡2  B2+tan⁡2  C2{\tan ^2}\,\,\frac{A}{2} + {\tan ^2}\,\,\frac{B}{2} + {\tan ^2}\,\,\frac{C}{2}, is If A>0,   B>0A > 0,\,\;B > 0 and A+B=π3A + B = \frac{\pi }{3}, then the maximum value of tan⁡A  tan⁡B\tan A\,\,\tan B, is

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