JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

Let

x=2

be a root of the equation

x^{2}+p x+q=0

and

f(x)-\left\{\begin{array}{cc} \frac{1-\cos \left(x^{2}-4 p x+q^{2}+8 q+16\right)}{(x-2 p)^{4}}, & x \neq 2 p \\ 0, & , x=2 p \end{array}\right.

Then

\lim\limits_{x \to 2{p^ + }} [f(x)]

,
where [.] denotes greatest integer function, is

View answer and explanation

Correct option: C

Option C (0) is correct because the limit of the function as x approaches 2p from the right is 1/2, and the greatest integer function of 1/2 is 0.

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