JEE PHYSICS MCQ: WAVE OPTICS

1 Hard

1 of 1

Application +4 | -1

In YDSE of equal width slits, if intensity at the centre of screen is

I_0

, then intensity at a distance of

\beta / 4

from the central maxima is (

\beta

is the fringe width):

View answer and explanation

Correct option: B

\frac{I_0}{2}

Option B (

\frac{I_0}{2}

) is correct because at a distance of β/4 from the central maxima, the phase difference is π/2, and the resulting intensity is half of the maximum intensity.

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