JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

E

L

M

and

G

denote the quantities as energy, angular momentum, mass and constant of gravitation respectively, then the dimension of

P

in the formula

P = E{L^2}{M^{ - 5}}{G^{ - 2}}

View answer and explanation

Correct option: D

\left[ {{M^0}{L^0}{T^0}} \right]

Option D (

\left[ {{M^0}{L^0}{T^0}} \right]

) is correct because after substituting the dimensions of each quantity, the resulting dimension of P is dimensionless.

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