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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
Find the number of 5 digited numbers that can be formed using 2, 2, 3, 3, 4
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Correct option: B
5!2!2!\frac{5 !}{2 ! 2 !}
Option B (5!2!2!\frac{5 !}{2 ! 2 !}) is correct because it accounts for the repetitions of the digits 2 and 3.

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