JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim\limits_{x \to 0} \frac{{\left[ {\left( {a - n} \right)nx - \tan x} \right]\sin nx}}{{{x^2}}} = 0

, where

n

is non-zero real number, then a is equal to

View answer and explanation

Correct option: D

n + \frac{1}{n}

Option D (

n + \frac{1}{n}

) is correct because substituting the limit into the given equation and solving for 'a' yields this result.

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