JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

The pair of lines

\sqrt{3} x^2-4 x y+\sqrt{3} y^2=0

are rotated about the origin by

\frac{\pi}{6}

in the anti-clockwise sense.
The equation of the pair in the new position is

View answer and explanation

Correct option: C

\sqrt{3} x^2-x y=0

The correct answer is C (

\sqrt{3} x^2-x y=0

) because rotating the pair of lines by

\frac{\pi}{6}

results in the equation

\sqrt{3} x^2-x y=0

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