For reducing one mole of ${\rm{F}}{{\rm{e}}^{2 + }}$ion to $Fe$, the number of faraday of electricity is :

JEE CHEMISTRY MCQ: REDOX REACTIONS

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For reducing one mole of

\mathrm{F}{\mathrm{e}^{2 + }}

ion to

Fe

, the number of faraday of electricity is :

View answer and explanation

Correct option: A

Option A (2) is correct because reducing one mole of

\mathrm{F}{\mathrm{e}^{2 + }}

Fe

requires 2 moles of electrons, which corresponds to 2 Faradays of electricity.

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