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JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

1 Easy
1 of 1
Application +4 | -1
All chords of the curve 3x2−y2−2x+4y=03{x^2} - {y^2} - 2x + 4y = 0 which subtend a right angle at the origin, pass through the fix point
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Correct option: B
(1,-2)
The correct answer is A (1,-2) because the equation of the chord is used to homogenize the given curve equation, and then the condition for the lines to be perpendicular is applied to find the fixed point.

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