JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

An ellipse is drawn by taking a diameter of the circle

(x-1)^2+y^2=1

as its semi-minor axis and diameter of the circle

x^2+(y-2)^2=4

is semi-major axis. If the centre of the ellipse is at the origin and its axes are the coordinate axes, then the equation of the ellipse is

View answer and explanation

Correct option: D

x^2+4 y^2=16

Option D (

x^2+4 y^2=16

) is correct because it correctly uses the diameters of the given circles as the semi-major and semi-minor axes of the ellipse.

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

P

9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O