$\mathop {\lim }\limits_{x \to 1} \left( {\frac{{1 + \cos \pi x}}{{{{\tan }^2}\pi x}}} \right) = $

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim\limits_{x \to 1} \left( {\frac{{1 + \cos \pi x}}{{{{\tan }^2}\pi x}}} \right) =

View answer and explanation

Correct option: D

\frac{1}{2}

Option D (

\frac{1}{2}

) is correct because after simplification and applying the limit, the expression evaluates to 1/2.

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