Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
1 of 1
Analyzing +4 | -1
If ∣x∣<1\left| x \right| < 1 and ∣y∣<1,\left| y \right| < 1, the sum to infinity of the sequence x+y,(x2+xy+y2),(x3+x2y+y3),…,x + y,\left( {{x^2} + xy + {y^2}} \right),\left( {{x^3} + {x^2}y + {y^3}} \right), \ldots , is
View answer and explanation
Correct option: A
x+y−xy1−x−y+xy\frac{{x + y - xy}}{{1 - x - y + xy}}
Option A (x+y−xy1−x−y+xy\frac{{x + y - xy}}{{1 - x - y + xy}}) is correct because it represents the sum to infinity of the given sequence under the conditions ∣x∣<1|x| < 1 and ∣y∣<1|y| < 1.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.