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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Application +4 | -1
Let f:R→Rf:R \to R be a differentiable function and f(1)=4f\left( 1 \right) = 4. Then, the value of lim⁡x→1  ∫4f(x)  2 tx−1  dt\lim\limits_{x \to 1} \,\,\int \nolimits_4^{f\left( x \right)} \,\,\frac{{2\,t}}{{x - 1}}\,\,dt〗is
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Correct option: A
8  f′  (1)8\,\,f'\,\,\left( 1 \right)
Option A (8f′(1)8 f'(1)) is correct because it is the result of applying L'Hopital's rule and the Fundamental Theorem of Calculus to the given limit.

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