JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

1 Hard

1 of 1

Application +4 | -1

A parallel plate capacitor of plate separation 2 mm is connected in on electric circuit having source voltage 400 volts. It the plate area is

60\,c{m^2}

, then the value of displacement current for

{10^{ - 6}}

sec. will be

View answer and explanation

Correct option: B

1.062 \times {10^{ - 2}}\mathrm{ amp}

Option B (

1.062 \times {10^{ - 2}}\mathrm{ amp}

) is correct because it is the value of displacement current calculated using the formula

{I_D} = { \in _\mathrm{o}}\frac{{\partial {\phi _E}}}{{\partial t}}

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