JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

Let the perpendiculars from any point on the line

2x + 11y = 5

upon the lines

24x + 7y - 20 = 0

and

4x - 3y - 2 = 0

have the lengths

{p_1}

and

{p_2}

respectively. Then,

View answer and explanation

Correct option: B

{p_1} = {p_2}

Option B (

{p_1} = {p_2}

) is correct because the line

2x + 11y = 5

is the angle bisector of the two lines, hence the perpendicular distances are equal.

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x-3 y=p, a x+2 y=q

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\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

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x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0