JEE MATHEMATICS MCQ: LIMITS

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\lim \limits_{{x \rightarrow 1}} \frac{\sin ^2\left(x^3+x^2+x-3\right)}{1-\cos \left(x^2-4 x+3\right)}

has the value equal to

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Correct option: A

Option A (18) is correct because after applying L'Hopital's rule and simplifying, the limit evaluates to 18.

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